ANISOTROPIC SPACE DYNAMICS · CANONICAL THEORY

Dynamics · Energy and Action

Retain the work integral and substitution, distinguish energy differences from rest energy, and construct and check the free Lagrangian.

Based on the final manuscript · Chapter 2

TheoryTheory · DERIVEDReviewMathematical review · CONDITIONALEvidenceEvidence · UNTESTEDCanonicalYesStatus, review and sources

Work done by external forces enters the joint motion reconstruction of the core and accompanying field. Integrating dEk=v⋅dpdE_k=\mathbf v\cdot d\mathbf p gives kinetic energy; adding the stored energy of the same rest structure yields Chapter 2’s continuous energy–momentum construction.

01Premises and energy reference · Starting Assumptions

A1 · Assumption

Retain the derived momentum and work definition

Use p=m0γv\mathbf p=m_0\gamma\mathbf v and dEk=v⋅dpdE_k=\mathbf v\cdot d\mathbf p. The background is uniform, internal state fixed, and net radiative loss absent. Set kinetic energy to zero at v=0v=0. Source: Eqs. (2.14) and (2.22).

A2 · Assumption

Declare the rest-energy normalization separately

For total energy, Chapter 2 adopts E0=m0c2E_0=m_0c^2. This is not needed to integrate the kinetic-energy difference. It is a normalization input linking static structural energy to the inertia parameter. Source: text between Eqs. (2.23) and (2.24).

02From momentum to work · Work Integral

Differentiate p=m0γvp=m_0\gamma v:

dpdv=m0(γ+γ3v2c2)=m0γ3.\frac{dp}{dv}=m_0\left(\gamma+\gamma^3\frac{v^2}{c^2}\right)=m_0\gamma^3.

Kinetic energy from rest to speed vv is therefore:

ASD-WEB-DYN-017
dEk=v⋅dp,Ek=m0∫0vw dw(1−w2/c2)3/2\mathrm dE_k=\mathbf v\cdot\mathrm d\mathbf p,\qquad E_k=m_0\int_0^v\frac{w\,\mathrm dw}{(1-w^2/c^2)^{3/2}}

Mathematical result
Set kinetic energy to zero at v=0; w is the integration speed.
Chapter reference: Final collected manuscript · Chapter 2 §III.4 (2.22) · ASD-BOOK-ddbade997b45

ww is the integration speed. For a general change of direction, v⋅dp\mathbf v\cdot d\mathbf p retains only the speed-changing component. Under the stated conditions, kinetic energy is a function of speed.

03Essential integration steps · Intermediate Steps

Set z=1−w2/c2z=1-w^2/c^2, giving w dw=−c2dz/2w\,dw=-c^2dz/2. The lower limit w=0w=0 gives z=1z=1, and the upper limit w=vw=v gives z=1−v2/c2z=1-v^2/c^2:

Ek=−m0c22∫11−v2/c2z−3/2 dz=−m0c22[−2z−1/2]11−v2/c2=m0c2[(1−v2c2)−1/2−1].\begin{aligned} E_k&=-\frac{m_0c^2}{2}\int_1^{1-v^2/c^2}z^{-3/2}\,dz\\ &=-\frac{m_0c^2}{2}\left[-2z^{-1/2}\right]_1^{1-v^2/c^2}\\ &=m_0c^2\left[\left(1-\frac{v^2}{c^2}\right)^{-1/2}-1\right]. \end{aligned}

This is the unnumbered calculation following manuscript Eq. (2.22); it does not work backwards from a standard energy formula.

ASD-WEB-DYN-018
Ek=m0c2(γ−1)=m0v22+3m0v48c2+O ⁣(m0v6c4)E_k=m_0c^2(\gamma-1)=\frac{m_0v^2}{2}+\frac{3m_0v^4}{8c^2}+O\!\left(\frac{m_0v^6}{c^4}\right)

Mathematical result
Follows from the momentum–work integral without first specifying rest energy.
Chapter reference: Final collected manuscript · Chapter 2 §III.4 (2.23); low-speed series expanded on the website · ASD-BOOK-ddbade997b45

Using γ=1+β2/2+3β4/8+O(β6)\gamma=1+\beta^2/2+3\beta^4/8+O(\beta^6) recovers Newtonian kinetic energy and its next correction. Both coefficients come from the expansion of one function.

04Rest energy and total energy · Rest and Total Energy

Normalization

Static structural energy requires independent matching

ASD treats a structure at rest as carrying strain and structural energy. To connect this energy to its inertia parameter, the chapter adopts:

ASD-WEB-DYN-019
E0=m0c2E_0=m_0c^2

Normalization
The energy–inertia normalization adopted in the chapter; the work integral alone supplies energy differences.
Chapter reference: Final collected manuscript · Chapter 2 §III.4 (2.24) and the preceding energy–inertia normalization · ASD-BOOK-ddbade997b45

The work integral determines energy differences and cannot fix E0E_0 by itself. With this normalization:

ASD-WEB-DYN-020
E=E0+Ek=m0c2γE=E_0+E_k=m_0c^2\gamma

Mathematical result
Explicitly depends on the rest-energy normalization.
Chapter reference: Final collected manuscript · Chapter 2 §III.4 (2.24) · ASD-BOOK-ddbade997b45

Thus E=m0γc2E=m_0\gamma c^2 combines the kinetic-energy result and A2. A microscopic theory must compute E0E_0 and m0m_0 from the same stable structural solution to test the normalization; it is not a fact established by this integral alone.

05Energy–momentum consistency · Algebraic Consistency

E2−c2p2=m02c4γ2(1−v2c2)=m02c4.E^2-c^2p^2 =m_0^2c^4\gamma^2\left(1-\frac{v^2}{c^2}\right) =m_0^2c^4.
ASD-WEB-DYN-021
E2−c2p2=m02c4E^2-c^2p^2=m_0^2c^4

Mathematical result
Eliminate v from the obtained p and E; this chapter does not assume it as a spacetime interval or starting axiom.
Chapter reference: Final collected manuscript · Chapter 2 §III.4 (2.24a) · ASD-BOOK-ddbade997b45

This is an algebraic consistency relation after eliminating vv. In this chapter it follows pp and EE; a presumed Minkowski invariant does not replace ASD’s constitutive derivation.

06Free-motion action · Free Lagrangian

Require the free translational Lagrangian to satisfy ∂L0/∂v=p\partial\mathcal L_0/\partial\mathbf v=\mathbf p. Integrate over speed:

L0(v)−L0(0)=∫0vm0w1−w2/c2 dw=m0c2(1−1−v2/c2).\mathcal L_0(v)-\mathcal L_0(0) =\int_0^v\frac{m_0w}{\sqrt{1-w^2/c^2}}\,dw =m_0c^2\left(1-\sqrt{1-v^2/c^2}\right).

Fix the constant with L0(0)=−E0=−m0c2\mathcal L_0(0)=-E_0=-m_0c^2, giving:

ASD-WEB-DYN-022
L0=−m0c21−v2/c2,p=∂L0∂v,E=p⋅v−L0\mathcal L_0=-m_0c^2\sqrt{1-v^2/c^2},\qquad\mathbf p=\frac{\partial\mathcal L_0}{\partial\mathbf v},\qquad E=\mathbf p\cdot\mathbf v-\mathcal L_0

Mathematical result
The integration constant is fixed by L₀(0)=−E₀; 𝓛₀ denotes a Lagrangian, distinct from length L.
Chapter reference: Final collected manuscript · Chapter 2 §III.4 (2.24b) · ASD-BOOK-ddbade997b45

Direct differentiation recovers m0γvm_0\gamma\mathbf v. The Legendre transform gives

p⋅v−L0=m0c2(γβ2+1γ)=m0c2γ.\mathbf p\cdot\mathbf v-\mathcal L_0 =m_0c^2\left(\gamma\beta^2+\frac1\gamma\right) =m_0c^2\gamma.

The website uses L0\mathcal L_0 to distinguish the Lagrangian from length LL; it corresponds to L0L_0 in manuscript Eq. (2.24b). Its low-speed expansion is

L0=−m0c2+m0v22+m0v48c2+O ⁣(m0v6c4).\mathcal L_0=-m_0c^2+\frac{m_0v^2}{2}+\frac{m_0v^4}{8c^2}+O\!\left(\frac{m_0v^6}{c^4}\right).

Chapter 2’s later orbital calculation must retain the v4v^4 term alongside gravitational terms of the same order. This module supplies that interface without developing the orbital approximation here.

07Physical meaning, scope and review · Interpretation and Review

Kinetic energy describes reconfiguration of the moving structure; rest energy describes the static core and accompanying structure. Matching mathematical forms do not remove these distinct physical roles.

For 0≤v<c0\leq v<c and positive fixed m0m_0, Ek≥0E_k\geq0, E(0)=E0E(0)=E_0 and dEk/dt=F⋅vdE_k/dt=\mathbf F\cdot\mathbf v. Divergence as v→cv\to c is a feature within this model, not an account of crossing that boundary. Radiation, internal excitation and background changes require an expanded energy balance.

Human review concerns whether inertia closure and static energy derived from one microscopic structure support the common normalization. That question is distinct from the correctness of the definite integral; see OP-DYN-01 (Chinese) · Chinese original.

08Sources and experimental interface · Sources

This page follows Chapter 2 §III, final manuscript §III, Eqs. (2.22)–(2.24b) and the unnumbered intermediate steps. Universal coupling of energy, inertial and gravitational mass is discussed in Experimental Relations.

On this page
STATUS & REVIEW
Theory StatusTheory · DERIVED
Mathematical ReviewMathematical review · CONDITIONAL
Overall Evidence StatusEvidence · UNTESTED
Canonical ASDYes · canonical theory baselinePreface · Chapters 1–2
Mathematical Review Note

Momentum follows after the inertial constitutive closure; total energy additionally uses E₀ = m₀c². These inputs remain explicit and require microscopic matching.

Read the formal review items
Adopted source, conditions and previous versions

§III.4 (2.22)—(2.24b)

Core–accompanying-field inertial constitution, momentum integration, inverse force response and energy; retain correct existing derivations.

Conditions retained in this adoption

  • Uniform background, fixed internal state, 0≤v<c and no net radiation.
  • The LVE directional law and inertial angular weight are separate inputs.
  • m₀=C_m m_def; adopt C_m=1 and universal mass normalization.

Specific unresolved source issues

  • The microscopic core profile, inertial weight and four mass responses still require one common structural solution.

Source locators: p0654 · p0656 · p0658 · p0660 · p0661 · p0663 · p0666 · p0936

Manuscript SHA-256: ddbade997b45913248e588953b1d27ccb9c7c206c3c8d992d3aef2364a64836e

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FND-3dde8d8e081d · Chapter 2, §III, Eqs. (2.22)–(2.24b) and unnumbered intermediate steps, PDF pp. 9–10

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Chapter 2 · §III.4 (2.22)—(2.24b)

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ASD: Dynamics · Energy and Action. ASD-DOC-EN-THEORY-DYNAMICS-ENERGY. Version 1.0.0; 2026-10-24. https://asd-physics.org/en/theory/dynamics/energy. §III.4 (2.22)—(2.24b). Source ASD-BOOK-ddbade997b45.

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